electric work
Work is done by emf source. Voltage of emf source determines the work done by it
$W=q\cdot V$
In a circuit: $q=I\cdot t$
$W=V\cdot I\cdot t$ work in electric circuit
$[W]=\frac{J}{C}\cdot \frac{C}{s} \cdot s = J$
In practice: $[W]=\text{kWh}$
$$\underset{( \text{P}\cdot \text{t} ) }{ 1\text{kWh} } =1000\text{W}\cdot 3600\text{s}=3,6 \cdot 10^{6}\text{J}$$
electric power