Dynamics of SHM

Last updated 2023.01.10 Edit Source

• Physics
• Dynamics
• Harmonic motion

$F_{spring}=kx=ma=\omega^2x$
$k=\omega^2m$
$\omega^2=\frac{k}{m}$ → $\omega=\sqrt{\frac{k}{m}}$

Period of SMH
$T=\frac{5\pi}{\omega}=\frac{2\pi}{\frac{k}{m}}=2\pi\sqrt{\frac{m}{k}}$